Convert megaelectron-volt to foot-pound
megaelectron-volt
Definition: Megaelectron-volt is a measure of energy, work, or heat. For conversion purposes, its value is 1.6021766339999e-13 times the reference unit, joule.
foot-pound
Definition: A foot-pound (ft·lb or ft·lbf) is a unit of work or energy in the imperial and United States customary systems of units. It is defined as the energy transferred when a force of one pound-force is applied over a linear displacement of one foot.
History/origin: The foot-pound is an English Engineering unit that is part of the British Gravitational system, based on the foot-pound-second (FPS) system. The FPS system is built using the units of foot for length, avoirdupois pound for mass or force, and the second for time.
Current use: The foot-pound is used in countries that have not adopted the International System of Units (SI). The United States is one of the largest countries where the foot-pound is still used in certain applications, though even in the US, the joule is preferred in most scientific contexts.
megaelectron-volt to foot-pound Conversion Table
| megaelectron-volt [MeV] | foot-pound [ft*lbf] |
|---|---|
| 0.01 megaelectron-volt | 0.000000 foot-pound |
| 0.10 megaelectron-volt | 0.000000 foot-pound |
| 1 megaelectron-volt | 0.000000 foot-pound |
| 2 megaelectron-volt | 0.000000 foot-pound |
| 3 megaelectron-volt | 0.000000 foot-pound |
| 5 megaelectron-volt | 0.000000 foot-pound |
| 10 megaelectron-volt | 0.000000 foot-pound |
| 20 megaelectron-volt | 0.000000 foot-pound |
| 50 megaelectron-volt | 0.000000 foot-pound |
| 100 megaelectron-volt | 0.000000 foot-pound |
| 1000 megaelectron-volt | 0.000000 foot-pound |
How to Convert megaelectron-volt to foot-pound
1 megaelectron-volt = 0.000000 foot-pound
1 foot-pound = 8462350027632 megaelectron-volt
Example
Convert 15 megaelectron-volt to foot-pound:
15 megaelectron-volt = 15 × 0.000000 foot-pound = 0.000000 foot-pound
