Convert foot-pound to megaelectron-volt
foot-pound
Definition: A foot-pound (ft·lb or ft·lbf) is a unit of work or energy in the imperial and United States customary systems of units. It is defined as the energy transferred when a force of one pound-force is applied over a linear displacement of one foot.
History/origin: The foot-pound is an English Engineering unit that is part of the British Gravitational system, based on the foot-pound-second (FPS) system. The FPS system is built using the units of foot for length, avoirdupois pound for mass or force, and the second for time.
Current use: The foot-pound is used in countries that have not adopted the International System of Units (SI). The United States is one of the largest countries where the foot-pound is still used in certain applications, though even in the US, the joule is preferred in most scientific contexts.
megaelectron-volt
Definition: Megaelectron-volt is a measure of energy, work, or heat. For conversion purposes, its value is 1.6021766339999e-13 times the reference unit, joule.
foot-pound to megaelectron-volt Conversion Table
| foot-pound [ft*lbf] | megaelectron-volt [MeV] |
|---|---|
| 0.01 foot-pound | 84623500276 megaelectron-volt |
| 0.10 foot-pound | 846235002763 megaelectron-volt |
| 1 foot-pound | 8462350027632 megaelectron-volt |
| 2 foot-pound | 16924700055264 megaelectron-volt |
| 3 foot-pound | 25387050082895 megaelectron-volt |
| 5 foot-pound | 42311750138159 megaelectron-volt |
| 10 foot-pound | 84623500276318 megaelectron-volt |
| 20 foot-pound | 169247000552635 megaelectron-volt |
| 50 foot-pound | 423117501381588 megaelectron-volt |
| 100 foot-pound | 846235002763175 megaelectron-volt |
| 1000 foot-pound | 8462350027631750 megaelectron-volt |
How to Convert foot-pound to megaelectron-volt
1 foot-pound = 8462350027632 megaelectron-volt
1 megaelectron-volt = 0.000000 foot-pound
Example
Convert 15 foot-pound to megaelectron-volt:
15 foot-pound = 15 × 8462350027632 megaelectron-volt = 126935250414476 megaelectron-volt
